Delay time calculation for reverberation¶
- Author or source: Andy Mucho
- Created: 2002-01-17 02:19:54
This is from some notes I had scribbled down from a while back on
automatically calculating diffuse delays. Given an intial delay line gain
and time, calculate the times and feedback gain for numlines delay lines..
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 | int numlines = 8;
float t1 = 50.0; // d0 time
float g1 = 0.75; // d0 gain
float rev = -3*t1 / log10 (g1);
for (int n = 0; n < numlines; ++n)
{
float dt = t1 / pow (2, (float (n) / numlines));
float g = pow (10, -((3*dt) / rev));
printf ("d%d t=%.3f g=%.3f\n", n, dt, g);
}
/*
The above with t1=50.0 and g1=0.75 yields:
d0 t=50.000 g=0.750
d1 t=45.850 g=0.768
d2 t=42.045 g=0.785
d3 t=38.555 g=0.801
d4 t=35.355 g=0.816
d5 t=32.421 g=0.830
d6 t=29.730 g=0.843
d7 t=27.263 g=0.855
To go more diffuse, chuck in dual feedback paths with a one cycle delay
effectively creating a phase-shifter in the feedback path, then things get
more exciting.. Though what the optimum phase shifts would be I couldn't
tell you right now..
*/
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