### 3rd order Spline interpollation

References : Posted by Dave from Muon Software, originally from Josh Scholar
Notes :
(from Joshua Scholar about Spline interpollation in general...)
According to sampling theory, a perfect interpolation could be found by replacing each sample with a sinc function centered on that sample, ringing at your target nyquest frequency, and at each target point you just sum all of contributions from the sinc functions of every single point in source.
The sinc function has ringing that dies away very slowly, so each target sample will have to have contributions from a large neighborhood of source samples. Luckily, by definition the sinc function is bandwidth limited, so once we have a source that is prefilitered for our target nyquest frequency and reasonably oversampled relative to our nyquest frequency, ordinary interpolation techniques are quite fruitful even though they would be pretty useless if we hadn't oversampled.

We want an interpolation routine that at very least has the following characteristics:

1. Obviously it's continuous. But since finite differencing a signal (I don't really know about true differentiation) is equivalent to a low frequency attenuator that drops only about 6 dB per octave, continuity at the higher derivatives is important too.

2. It has to be stiff enough to find peaks when our oversampling missed them. This is where what I said about the combination the sinc function's limited bandwidth and oversampling making interpolation possible comes into play.

I've read some papers on splines, but most stuff on splines relates to graphics and uses a control point descriptions that is completely irrelevant to our sort of interpolation. In reading this stuff I quickly came to the conclusion that splines:

1. Are just piecewise functions made of polynomials designed to have some higher order continuity at the transition points.

2. Splines are highly arbitrary, because you can choose arbitrary derivatives (to any order) at each transition. Of course the more you specify the higher order the polynomials will be.

3. I already know enough about polynomials to construct any sort of spline. A polynomial through 'n' points with a derivative specified at 'm[1]' points and second derivatives specified at 'm[2]' points etc. will be a polynomial of the order n-1+m[1]+m[2]...

A way to construct third order splines (that admittedly doesn't help you construct higher order splines), is to linear interpolate between two parabolas. At each point (they are called knots) you have a parabola going through that point, the previous and the next point. Between each point you linearly interpolate between the polynomials for each point. This may help you imagine splines.

As a starting point I used a polynomial through 5 points for each knot and used MuPad (a free Mathematica like program) to derive a polynomial going through two points (knots) where at each point it has the same first two derivatives as a 4th order polynomial through the surrounding 5 points. My intuition was that basing it on polynomials through 3 points wouldn't be enough of a neighborhood to get good continuity. When I tested it, I found that not only did basing it on 5 point polynomials do much better than basing it on 3 point ones, but that 7 point ones did nearly as badly as 3 point ones. 5 points seems to be a sweet spot.

However, I could have set the derivatives to a nearly arbitrary values - basing the values on those of polynomials through the surrounding points was just a guess.

I've read that the math of sampling theory has different interpretation to the sinc function one where you could upsample by making a polynomial through every point at the same order as the number of points and this would give you the same answer as sinc function interpolation (but this only converges perfectly when there are an infinite number of points). Your head is probably spinning right now - the only point of mentioning that is to point out that perfect interpolation is exactly as stiff as a polynomial through the target points of the same order as the number of target points.
Code :
//interpolates between L0 and H0 taking the previous (L1) and next (H1)
points into account
inline float ThirdInterp(const float x,const float L1,const float L0,const
float H0,const float H1)
{
return
L0 +
.5f*
x*(H0-L1 +
x*(H0 + L0*(-2) + L1 +
x*( (H0 - L0)*9 + (L1 - H1)*3 +
x*((L0 - H0)*15 + (H1 -  L1)*5 +
x*((H0 - L0)*6 + (L1 - H1)*2 )))));
}

from : a[AT]a[DOT]com
comment : What is x ?

from : mike_rawes[AT]ku[DOT]oc[DOT]oohay
comment : The samples being interpolated represent the wave amplitude at a particular instant of time, T - an impulse train. So each sample is the amplitude at T=0,1,2,3 etc. The purpose of interpolation is to determine the amplitude, a, for an arbitrary t, where t is any real number: p1 p0 a n0 n1 : : : : : 0-------1---t---2-------3------> T : : : : <-x-> x = t - T(p0) - myk

from : mike_rawes[AT]ku[DOT]oc[DOT]oohay
comment : Dang! My nice diagram had its spacing stolen, and it now makes no sense! p1, p0, n0, n1 are supposed to line up with 0,1,2,3 respectively. a is supposed to line up with the t. And finally, <-x-> spans between 1 and t. - myk

from : fcanessa[AT]terra[DOT]cl
comment : 1.- What is 5f ? 2.- How I can test this procedure?. Thank you

from : joshscholar_REMOVE_THIS[AT]yahoo[DOT]com
comment : This is years later. but just in case anyone has the same problem as fcanessa... In C or C++ you can append an 'f' to a number to make it single precision, so .5f is the same as .5

from : cdion[AT]quantum-music[DOT]ca
comment : About that thing you've said "5 point seems to be the sweet spot". Well, it might depends on the sampling rate.

from : claude[AT]yourfreemail[DOT]stream
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